[理工] 【電子學】MOS差動對

看板Grad-ProbAsk作者 (Avanlandis)時間13年前 (2012/04/03 21:29), 編輯推噓0(000)
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題目: In this example we consider the design of the current source that supplies the bias current of a MOS differential amplifier.Let it be required to achieve a CMRR of 100dB and assume that the only source of mismatch between Q1 and Q2 is a 2% mismatch in their W/L ratios. Let I = 200uA and assume that all transistors are to be operated at Vov = 0.2V. For the 0.18-um CMOS fabrication process available. VA'=5 V/um. (1)If a simple current source is utilized for I,what is the required value of "channel length"? (2)If a cascode current source is utilized,what's the channel length of the two transistors in the cascode? --------------- (1)小題書上的算法求gm時: gm = 2ID/Vov = 2 x (I/2) /Vov = 2 x 0.1 /0.2 = 1m A/V, 但(2)小題時 gm = 2I/Vov = 2 x 0.2 / 0.2 = 2m A/V , 想請問為何current source的構造從單一MOS變成CASCODE的形式時,流過的I 卻變為兩倍? 目前的想法解讀是:因為cascode兩顆MOS串聯,所以Leq = 2L,所以電流將會是 使用一個MOS的0.5倍..,但是這...只會讓電流變小阿= ="(今天上課老師 剛好有提到這個,但不是電子學的課..) 感謝各位!! -- 慵懶地望著天空,奢望自己能更堅強 人生..何嘗不就是不斷的擺脫眼前的阻撓 然而,終究有天得回歸原本的最初~ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 1.175.152.180 ※ 編輯: kela12340 來自: 1.175.152.180 (04/03 21:50)
文章代碼(AID): #1FUlidle (Grad-ProbAsk)