[理工] 台科大100離散

看板Grad-ProbAsk作者 (J)時間14年前 (2012/01/05 17:37), 編輯推噓1(102)
留言3則, 2人參與, 最新討論串1/1
let G be a bipartite graph whose vertices are divided into two sets A and B, where no two vertices in the same set are connected. Prove that if G contains a Hamiltonian path, then the number of vertives in A and the number of vertices in B differ by at most 1. (Hint:What is a Hamiltonian path?) 雖然這題有個提示不過還是不知道從哪裡開始證起@@" -- -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.34.232.57

01/05 20:10, , 1F
用矛盾證法 假設A和B vertex差2以上,然後根據hamilton
01/05 20:10, 1F

01/05 20:11, , 2F
path的定義,可以證明不可能找到一條path經過所有頂點
01/05 20:11, 2F

01/05 23:05, , 3F
阿~ 原來這題是在考你雙分圖定義熟不熟XD 謝謝>"<
01/05 23:05, 3F
文章代碼(AID): #1F1MztAF (Grad-ProbAsk)