[理工] [工數]二階ODE
y''+xy'-2y = 1 y(0) = 1 y'(0) = 2
x e^-(t^2 / 2)
y(x) = 3/2(x^2 +1) + 2(x^2 + 1)∫ ────── dt - 1/2
0 (t^2 + 1)^2
雖然這題答案很醜
但還是想請教板大這題下手的解法是怎麼解的
看到題目給y(0) y'(0)會聯想到Laplace 但轉出來並不好看
謝謝
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