[理工] [工數] 逆運算的問題
2
請問...若是 (D +1)y =sinx
1 ix
Im {--------- e }
D^2 + 1
ix 1
= Im {e ---------------- }
(D+i)^2 + 1
ix 1
= Im {e -----------}
D(D+2i)
ix 1
= Im {e --------- x } 長除法
(D+2i)
ix 1 D
= Im {e (---- - -------- ) x }
2i (2i)^2
ix x 1
= Im {e ---- - -------- }
2i (2i)^2
x 1
= Im (cosx + isinx) ( ------ + ---- )
2i 4
之後找虛部..但上式總有2項虛部如下:
(-ix cosx)/2 與 (isinx)/4
請問我錯在哪裡呢? 可否請大家幫我看看呢?
謝謝大家的幫忙!!
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