[商管] [統計] 98逢甲國貿

看板Grad-ProbAsk作者 (3Q的Orz冏)時間15年前 (2011/03/04 08:46), 編輯推噓0(006)
留言6則, 3人參與, 最新討論串1/1
題目: Two coins are simultaneously tossed until one of them comes up a head and the other a tail. The first coin comes up a head with probability 1/3 and the second with probability 1/2. All tosses are assumed independent. Let X be the number of tosses until the game is over. (A) Find the expected value and the variance of X. (B) Given the X is greater than 3, what is conditional probablity that X is greater than 5? ----------------------------------------------------------------------------- 個人想法: 這題我覺得是用幾何分配 X~Geo(p=1/6) pmf為 1/6 * (5/6)^(x-1) x=1,2,...,∞ 但是之後就卡住了 因為不會做x在指數的期望值和變益數... b小題則是沒有頭緒 我想是這樣 P(X>5︳X>3) 但是看起來就有問題 麻煩大家囉~ 謝謝~~ ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.170.6.180 ※ 編輯: wbesjdje 來自: 218.170.6.180 (03/04 08:47) ※ 編輯: wbesjdje 來自: 218.170.6.180 (03/04 08:55)

03/04 08:59, , 1F
期望值 變異數用m.g.f去算
03/04 08:59, 1F

03/04 10:17, , 2F
先把結果的宇集弄出來 2正 兩反 1正1反 算出機率
03/04 10:17, 2F

03/04 10:18, , 3F
接著就可以用幾何分配囉 第二小題
03/04 10:18, 3F

03/04 10:19, , 4F
考的是無記憶性 接著
03/04 10:19, 4F

03/04 10:20, , 5F
用反面的機率方法去解
03/04 10:20, 5F

03/06 16:50, , 6F
謝謝樓上幾位~~
03/06 16:50, 6F
文章代碼(AID): #1DS3PnEm (Grad-ProbAsk)