[理工][離散] 99政大資科

看板Grad-ProbAsk作者 (喜歡舒服笑容女孩)時間14年前 (2011/02/23 23:47), 編輯推噓1(103)
留言4則, 1人參與, 最新討論串1/1
1. let Kn denote a complete simple graph with n>0 vertices. then what is the length of a shortest circuit containing all edages of graph K2n ? 去年有人討論 但...答案到底是? 證明: Let G(V,E) be a directed multigraph such that E 不=空 and for all vertices x 屬於V ,in-degree(x)=out-degree(x) show that there exists a simple circuit of lengh>0 in G 該怎證? 我完全沒圖形想法 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 121.254.84.213

02/24 12:06, , 1F
1.應該是不存在這種circuit才對
02/24 12:06, 1F

02/24 12:09, , 2F
2.造一條maximal path p = <v1,v2,...,vm>
02/24 12:09, 2F

02/24 12:09, , 3F
因為 indeg(v1) = outdeg(v1) 所以存在2<=i<=m 使得
02/24 12:09, 3F

02/24 12:10, , 4F
vi連向v1 最後取Cycle c= <v1,v2,..,vi,v1>
02/24 12:10, 4F
文章代碼(AID): #1DPIlxXS (Grad-ProbAsk)