[理工] [機率統計] 99清大資應機率論(贈批幣500)

看板Grad-ProbAsk作者Hotpenis5566 (陪睡公車整型團體-SNS滴)時間13年前 (2011/02/11 12:18)推噓13(13推 0噓 28→)

留言41則, 4人參與討論串1/1

※ 引述《colan1206 (嵐)》之銘言： : 今年清大資應的機率論考題 : 困擾我很久>"< : 希望有大大能幫忙解題 : 非常感激"" 借我問>.<感謝希望機率很強的大大給我指正 1.The probability that any paticular hard disk will fail during its Kth year of use is given by the probability mass function for K. P(K) = p * (1-p) ^ (K-1) ,K=1,2,3,... (1)Four hard disks are tested simultaneously.Determine the probability that none of the four disks fails during its first year of use. 題目：問第一年四個硬碟沒有壞的機率是一個硬碟第一年壞掉的機率P(K)=P,四個硬碟則是P^4 第一年四個硬碟沒壞的機率則是1-P^4 對嗎?@@ (2)Four hard disks are tested simultaneously.Determine the probability that exactly two hard disks have faild by the end of the third year. 題目：問四個硬碟有兩個在第三年末壞掉兩個的機率一個硬碟在第三年末壞掉的機率P(K)=P*(1-P)^2 兩個硬碟是[P*(1-P)^2]^2 (3)Four hard disks are tested simultaneously.Determine the probability that exactly one hard disk fails during each of the first three years. 題目：一個硬碟在三年之內壞掉的機率 P(K)=P(1)+P(2)+P(3)=P+P(1-P)+P(1-P)^2=P[1+(1-P)+(1-P)^2] (4)Four hard disks are tested simultaneously.Given that one hard disk has failed by the end of the first year,determine the probability that exactly two hard disks have failed by the end of the third tear. 題目：P(第1年有一個硬碟壞掉|第三年有兩個硬碟壞掉) P(1) P P ---------------------- = -------------------- = ------------------ [P(3)]^2 [P(1-P)^2]^2 P^2*(1-P)^4 (5)Suppose that during the first three years the probability that a hard disk will fail is 0.488.What is the probability that a hard disk will fail during its first year of use? 不會... 我覺得我全錯= =.. 有人可以告訴我怎麼算嗎 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.161.51.228 ※ 編輯: Hotpenis5566 來自: 218.161.51.228 (02/11 12:19) ※ 編輯: Hotpenis5566 來自: 218.161.51.228 (02/11 12:20)

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