[理工] [工數] y''-(1-y^2)y'+y = 0
y''-(1-y^2)y'+y = 0 , y(0)=2,y'(0)=0。
我能試的都試了,還是找不到下手點...
謝謝
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※ 編輯: poo123456 來自: 140.135.43.31 (05/18 13:21)
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