Re: [理工] [線代]-eigenvalue證明&計算
原文恕刪 ....
: 5.Find a matrix B such that B^2 = A.
: ┌ ┐
: | 2 1|
: A = | |
: |-2 -1|
: └ ┘
Sol~
Step1:
-1 -1
求A之特徵值及特徵向量:得特徵值為1和0,特徵向量為 [ ] 及 [ ]
1 2
Step2:
-1 -1 -1 1 0 -1
取 P 為 [ ] , P A P = D = [ ] , A = P D P
1 2 0 0
Step3:
2 -1
B = A = P D P
┌ ┐
| 1/2 │
│ 1 0 │ -1
故 B = P │ │ P
| 1/2 │
| 0 0 │
└ ┘
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