Re: [理工] [工數]-向量
看板Grad-ProbAsk作者shinyhaung (我是Shiny)時間15年前 (2010/04/12 15:27)推噓14(14推 0噓 10→)留言24則, 10人參與討論串28/41 (看更多)
※ 引述《redwing119 (翼迷)》之銘言:
: ∫ yzcosxdx + zsinxdy + ysinxdz
: c
: where C is the line from (0 ,1, 2) to (π/2 , 2 , 4)
判別一下就知道為保守場
不受路徑影響
∫ yzcosxdx + zsinxdy + ysinxdz
c
= ∫ d(yzsinx)
c
|(π/2 , 2 , 4)
= yzsinx |
|(0 ,1, 2)
= 2*4*sin(π/2) - 1*2*sin(0)
= 8
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 112.105.70.225
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這要靠經驗XD
一般來說是用 ▽ x F = 0來判斷
不然就是dx dy dz前面的東西偏積分一下 有幾個未知數 就要出現幾次
※ 編輯: shinyhaung 來自: 112.105.70.225 (04/12 15:43)
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