[理工] [電磁] 電場 計算機按法與計算過程
電磁學-真空靜電的靜電場題目
→ ^ Q
E = aR ---------------
4πε0 R^2
.
.
. (過程)
.
.
→ 9 -9 [-0.4 , -0.1 , 0.2]
E = (9 X 10 ) X (5 X 10 ) ---------------------------------- ----(#)
(0.4^2 + 0.1^2 + 0.2^2)^3/2
寫到到這裡我就卡住了
9 -9
我用計算機先按(9 X 10 ) X (5 X 10 ) = 45 ------(1)
再按Ans鍵 ÷ (0.4^2 + 0.1^2 + 0.2^2)^3/2 = 2429.543246 ------(2)
-4
之後讓-0.4 ÷ (2) = -1.6464 x 10 (A)
-5
-0.1 ÷ (2) = -4.116 x 10 (B) ------(3)
-5
0.2 ÷ (2) = 8.232 x 10 (C)
算到(3)之後我就不會寫了,課本上是從(#)直接跳到答案
我嘗試把(3)加加減減來算,但數字大小差太多了,看來是(3)算錯了
請問過程要怎麼算???如何求解呢??
是用{(A)+(B)}ay{(A)-(B)}ax的方法求解嗎??
麻煩您了
→ ^ ^ ^
答案是E = - ax 187 - ay 46.76 + az 93.5 (V/M)
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