[理工] [控制]-清大96-根軌跡 5次方因式
96清大第一題 求根軌跡
G(s)=k s^2+2s+5
--------------
s(s+3)(s^2+s+1)
求到分離點 dG(s)
------- = 0
ds
解得 2s^5+10s^4+36s^3+65s^2+40s+15
因此分離點為s=-2.02 ,-1.12+ j2.96(不合) ,-0.36+ j0.49(不合)
- -
這是試題解析寫得答案
想請問
(1)5次方怎麼因式分解求s
(2)分離點為什麼有兩個(四個?)不合??
感謝解答!!
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