[問題] 計組-管線計算
請教一題計算
Suppose that 20% of the instruction are loads, and half of the time
the instruction following a load insruction depends on the result of
the lod. If this hazard creates a single-cycle delay, how much faster
is an idea pipelined machine (with CPI of 2) that does not delay the
pipeline, compard to this realistic pipeline that may create a single-
cycle load stall delay?(Ignore any stalls other than load stalls)
書上寫:
cpi=2+ 20% *50% *1 =2.1
perfect pipeline machine 快了 2.1/2=1.05
請教一下，cpi第一個式子，那個*1 是在乘什麼呢? 謝謝
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