[問題]請問如何作次數未知的加法?

看板Fortran作者nestea911399 (卡進無底洞)時間15年前 (2008/12/09 15:32)推噓9(9推 0噓 19→)

留言28則, 4人參與討論串1/1

以下是程式碼 CALL JUMP(DSMAX(MAT),DS) ! Determines segment length. CALL STEP(DS,DSEF,NCROSS) ! Moves particle to end of step. WRITE(17,*) N,MIN(DS,DSEF) ! 決定把DS 跟 DSEF的最小值寫入檔案但是現在有一個問題是, 我想把每一顆粒子的總距離加起來,即是第一顆的總距離,及第二顆的總距離例如 1 1.451336171889607E-007 1 1.625982843357572E-007 1 7.786647901384987E-008 1 6.001349813026089E-008 1 2.501697761188227E-008 2 1.989400815159079E-008 2 3.863321521894446E-008 2 2.358943701411900E-008 可是在N=1時有5個小距離 N=2 有3個小距離在程式裡要如何知道每一次所有的小距離,然後相加起來得到各別的N總距離謝謝 N=0 ! Shower counter. C CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC C ------------------------ Shower simulation starts here. C 101 CONTINUE N=N+1.0D0 C C ********** Set the initial state of the primary particle. C KPAR=KPARP X=X0 Y=Y0 Z=Z0 E=E0 CALL GCONE(U,V,W) ! Initial direction. C C **** Check if the trajectory intersects the material system. C CALL LOCATE IF(MAT.EQ.0) THEN CALL STEP(1.0D30,DSEF,NCROSS) IF(MAT.EQ.0) THEN ! The particle does not enter the system. PRIM(1)=PRIM(1)+1.0D0 GO TO 105 ENDIF ENDIF C C ************ Primary particle counters. C ILB(1)=1 ! Identifies primary particles. ILB(2)=0 ILB(3)=0 ILB(4)=0 ILB(5)=0 DO IC=1,7 COL(IC)=0.0D0 ! Numbers of events. ENDDO DO I=1,NBOD EDEP(I)=0.0D0 ! Energy deposited in each body. ENDDO C --------------------------------------------------------------------- C ------------------------ Track simulation begins here. C COMMON/TRACK/E,X,Y,Z,U,V,W,WGHT,KPAR,IBODY,MAT,ILB(5) CALL CLEANS ! Cleans the secondary stack. 102 CONTINUE CALL START ! Starts simulation in current medium. C 103 CONTINUE CALL JUMP(DSMAX(MAT),DS) ! Determines segment length. CALL STEP(DS,DSEF,NCROSS) ! Moves particle to end of step. WRITE(17,*) N,MIN(DS,DSEF) DS0=DS0+MIN(DS,DSEF) WRITE(36,*) N,DS0 ! DDSS=DDSS+MIN(DS,DSEF) C IF(MAT.EQ.0) THEN ! The particle has left the material system. IEXIT=1 ! Labels emerging particles. GO TO 104 ! Exit. ENDIF C IF(NCROSS.GT.0) GO TO 102 ! The particle crossed an interface. C CALL KNOCK(DE,ICOL) ! Simulates the interaction event. COL(ICOL)=COL(ICOL)+1.0D0 ! The interaction is counted. EDEP(IBODY)=EDEP(IBODY)+DE ! Deposited energy counter. IF(E.LT.EABS(KPAR,mat)) THEN ! The particle has been absorbed. IEXIT=2 ! Labels absorbed particles. GO TO 104 ! Exit. ENDIF GO TO 103 C ------------------------ The simulation of the track ends here. C --------------------------------------------------------------------- 104 CONTINUE C C ************ Increment particle counters. C IF(ILB(1).EQ.1) THEN PRIM(IEXIT)=PRIM(IEXIT)+1.0D0 DO KC=1,6 AVNI(KC,IEXIT)=AVNI(KC,IEXIT)+COL(KC) AVNI2(KC,IEXIT)=AVNI2(KC,IEXIT)+COL(KC)**2 ENDDO ELSE SEC(KPAR,IEXIT)=SEC(KPAR,IEXIT)+1.0D0 C C ------------------------ The simulation of the shower ends here. CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC C C **** Energies deposited in different bodies. C DO KB=1,NBOD EDEPT(KB)=EDEPT(KB)+EDEP(KB) VEDEPT(KB)=VEDEPT(KB)+EDEP(KB)**2 ENDDO C **** Deposited energy distributions in selected bodies or groups of C bodies (specific of each geometry). C In this case, EDEP(1,*) = Energy in body 1. EDISTR=EDEP(1) IF(EDISTR.GT.1.0D0) THEN ICH=1.0D0+EDISTR/DEBIN ICH=MIN(NCHD,ICH) EDEPD(1,ICH)=EDEPD(1,ICH)+1.0D0 ENDIF C 105 CONTINUE C C ---- End the simulation after the alloted time or after completing C DSIMS showers. CALL TIMER(TSEC) IF(TSEC.LT.TSECA.AND.N.LT.NTOT) GO TO 101 謝謝 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.114.106.110

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noway501

12/09 17:40, , 1^F

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noway501

12/09 17:42, , 2^F

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※ 編輯: nestea911399 來自: 140.114.106.110 (12/09 18:21)

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meteorology

12/09 18:22, , 3^F