[閒聊] Re: XSINX的積分? XSINAX的積分?
※ 引述《FBLZA (我還是很喜歡妳)》之銘言:
: Y?
xsinx => x sinx
1 -cosx
0 -sinx
=> -xcosx+sinx
xcosx => x cosx
1 sinx
0 -cosx
=> xsinx+cosx
xsinax => x sinax
1 -(1/a)cosax
0 -(1/a)^2sinax
=> -(1/a)xcosax+(1/a)^2sinax
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◆ From: 114.46.148.246
※ 編輯: zoo30223 來自: 114.46.148.246 (07/14 16:58)
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