[課業] c語言 運算元
int abc(int *k) {
*k += 4;
return 3 * ( *k) - 1;
}
void main() {
int i = 10, j = 10, result1, result2;
result1 = (i / 2) + abc( &i);
result2 = abc( &j) + (j / 2);
}
如果在運算式中的運算元估算的順序是由右到左，則result1，則result2的值為何?
看了補習班答案是 result1=48, result2=46
result1= (i/2) + abc(&i)
= (14/2) + 41 (*k=14; 3*14 - 1=41)
= 48
想問的是，為什麼在abc裹的計算是先乘除後加減呢
而不是由右到左推算呢
因為本題沒有提運算子優先權，是不是應該照題目要求一律從右到左呢
謝謝
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※ mike31830:轉錄至看板 Grad-ProbAsk 05/10 00:35
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