[課業] 102地方 基本電學
102地特基電36題
http://wwwc.moex.gov.tw/ExamQuesFiles/Question/102/102190_3515.pdf
答案(c) 10cos(377t+53度)
是否有錯呢? 應該是10cos(377t-53度)吧!!
V1(t)=6cos(377t)
V2(t)=8sin(377t)=8cos(90度-377t)=8cos(377t-90度)
向量式 v1+v2=6-j8=10 角度-53
求 V1(t)+V2(t) = 10cos(377t-53度)
以上是過程 如有錯誤請指教
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