[考題] 線性代數問題
矩陣
-1 2 0 4
0 -1 2 12
0 -1 2 12
-x1+2x2+4x4=0
-x2+2x3+12x4=0
求基底
4 4
2 0
答案 c1 1 c2 6
0 -1
不懂基底 如何求
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推
03/28 00:44, , 1F
03/28 00:44, 1F
→
03/28 01:19, , 2F
03/28 01:19, 2F
推
03/28 01:20, , 3F
03/28 01:20, 3F
→
03/28 07:37, , 4F
03/28 07:37, 4F
→
03/28 07:37, , 5F
03/28 07:37, 5F
推
03/28 07:43, , 6F
03/28 07:43, 6F
推
03/28 09:30, , 7F
03/28 09:30, 7F
→
03/28 11:20, , 8F
03/28 11:20, 8F
→
03/28 11:22, , 9F
03/28 11:22, 9F