[請益] 兩部訂價法的題目
題目:成本函數TC=20Q+600,面對兩群消費者A、B
A的需求函數:Pa=100-Qa
B的 :Pb=60-Qb
若老闆無法區別消費者是A或B,如何定會員費和使用費
答案是寫說直接以較小的消費者剩餘作為會員費,並以P>MC為使用費。
但是我以前補習老師有提兩種CASE
一種是CSa>2CSb
如果是這種情況就要以CSa為會員費,而非解答寫的以CS小的為會員費,
所以問題在於考試是否要把兩個CASE都算一遍才行?
就是CASE1:CSa>2CSb
CASE2:2CSb>CSa
解答寫的應該是屬於CASE2的情形,
但是難道不用兩種CASE都算一遍才能知道正確答案嗎?
是否有甚麼快速的判別方法?
還是固定就用較小的消費者剩餘作為會員費才是正解?
這個問題困擾我兩天了,
希望有版友能指點,
非常感謝!
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