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討論串non-zero exclusive count(Re: locking against myself in
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#3
Re: non-zero exclusive count(Re: locking against myself in
推噓0(0推 0噓 0→)留言0則，0人參與, 最新作者dillon.時間15年前 (2010/12/28 07:32), 編輯資訊
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Hmm. The inconsistency is probalby due to the secondary panics.. Run 'dmesg -M vmcore.21 -N kern.21', two panics occured at the same. time and their k
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#2
Re: non-zero exclusive count(Re: locking against myself in
推噓0(0推 0噓 0→)留言0則，0人參與, 最新作者dillon.時間15年前 (2010/12/28 02:01), 編輯資訊
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Here's a bug fix for the second bug... the recursive lock --mmap issue.. Please test it (with the originally suggested #if 0 workaround removed).. Thi
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#1
non-zero exclusive count(Re: locking against myself in
推噓0(0推 0噓 0→)留言0則，0人參與, 最新作者qhwt.時間15年前 (2010/12/27 13:01), 編輯資訊
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On Sun, Dec 26, 2010 at 11:09:17AM -0800, Matthew Dillon wrote:. > non-zero exclusive counts usually mean an extra lock release or a. > missing lock a
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