[習題] 1.13 (b)似乎不完整

看板Chang_Course作者 (xxx)時間18年前 (2007/11/07 15:51), 編輯推噓4(401)
留言5則, 3人參與, 最新討論串1/1
the answer: _ G P4-free, both G, G connected with min n(G) ___ G-v P4-free, so one of G-v and G-v is disconnected _ if G_v disconnceted, then v isolated in G......# ___ 可是還有一個case: 要是 G-v connected 當然 G-v disconnected. ex: C4 join 或許你可以假設 G-v= ▽ G_i, then ___ 1. v 至少會連到一個 component of G-v,since G connected _ 2. 而且每個G_i都會有一點不連到v, since G connceted 再由此去找出P4, 得到矛盾. p.s.我的做法是證明: If G connctedand P4-free, then G is a complete bipartite graph. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.231.114

11/08 02:13, , 1F
那是在不失一般性情況下的假設,你說的case
11/08 02:13, 1F

11/08 02:14, , 2F
也可以reduce成這種!
11/08 02:14, 2F

11/08 22:47, , 3F
\bar{G-v}=\bar{G}-v,這樣WLOG比較順吧?
11/08 22:47, 3F

11/09 23:40, , 4F
嗯嗯對!
11/09 23:40, 4F

11/10 01:02, , 5F
P4是自反同構,這樣G若是P4-free那G-bar也是
11/10 01:02, 5F
文章代碼(AID): #17CMveM- (Chang_Course)