[問題] 高精度等待時間
開發平台(Platform): (Ex: VC++, GCC, Linux, ...)
VC
問題(Question)：
我想要產生一筆仿類比的數位訊號，輸出頻率是 1E6 HZ
我還想要接收一筆類比資料，擷取頻率是 1E4 HZ
所以我開了兩個 thread 去分別執行任務
問題在於我使用 QueryPerformanceCounter 去當接收端擷取頻率的計時器
QueryPerformanceFrequency(&Freq);
QueryPerformanceCounter(&t1);
do{
QueryPerformanceCounter(&t2);
}while((t2.QuadPart-t1.QuadPart)/Freq.QuadPart>0.0001)
該寫法很耗CPU，造成輸出訊號的執行序不能輸出正確的訊號
即：
當time = 0 時，應該輸出 5 ，程式正確輸出 5
當time = 1 時，應該輸出5.0001，程式卻因為在執行另一條thread
就輸出上一筆資料的訊號 (因為該位置上的值沒被更改)
該怎麼解決這個問題呢?
是否有更好的寫法?
相同的問題 http://zhidao.baidu.com/question/296303137.html
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