[問題] 遞增和遞減的運算子
a的初值為10
(1)
遞增 b=a++;
一般 b=a; a=a+1;
結果 a=11,b=10
以上沒問題我看得懂
(2)
遞增 b=a--;
一般 b=a; a=a-1;
結果 a=10,b=9
照上面的(1)相比,a應該9,b應該是10才對吧!?
為什麼結果出來是 a=10,b=9呢?
(3)
int a=10,b=20,c=30
c+=--a - b++;
結果g=30+10-19=21 a=10 b=20
為什麼不是g=30+9+19 a=9 b=20
--a不是10-9=9嗎?
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