[問題] C語言 二進位轉十進位
開發平台(Platform): (Ex: VC++, GCC, Linux, ...)
Dev C++
額外使用到的函數庫(Library Used): (Ex: OpenGL, ...)
No
問題(Question)：
二進位轉十進位 輸入字元數超過10位數會變成負的
餵入的資料(Input)：
11111111111
預期的正確結果(Expected Output)：
2047
錯誤結果(Wrong Output)：
-1015
程式碼(Code)：(請善用置底文網頁, 記得排版)
#include<stdio.h>
#include<math.h>
int main()
{
long int input;
long int i,bit;
long int C_result=0;
printf("Input an integer containing only 0s and 1s: ");
scanf("%ld",&input);
for(i=0;input!=0;input/=10)
{
bit=input%2;
C_result=C_result + bit*pow(2,i);
i++;
}
printf("Result of convertion is %ld \n",C_result);
system("Pause");
return(0);
}
補充說明(Supplement)：
我覺得是int宣告的長度問題 但是我換成long int 還是無法
有請各位幫忙了~~
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