[問題] 關於c++的程式追蹤問題
# include <stdio.h>
main()
{
foo(7);
}
foo(int n)
{
if(n==10)
printf("done");
else
{ printf("%d",n);
foo(++n);
n--;
printf("%d",n);
}
}
答案是：7 8 9 done 9 8 7
可以請問這個程式是怎麼跑的嗎?
我算的流程是
(1)一開始7代入，跑else那段，印出7
(2)再跑遞迴foo(8)，印出8，...一直到foo(10)
疑問:為什麼印完done之後
後面要跟著印呢?
以上謝謝各位前輩的解說
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