[問題] 影像處理noise的問題

看板C_and_CPP作者yanqinru (髍鵀)時間15年前 (2009/04/09 09:50)推噓4(4推 0噓 9→)

留言13則, 3人參與討論串1/1

各位板友好小弟最近開始學習影像處理目前遇到了一些問題想請教各位以下有Impulse、Gaussuan、Uniform三個雜訊程式段想請問三個程式中for迴圈裡大概是在做什麼? 因為一直無法將理論和程式結合在一起又不確定自己的想法到底有沒有錯誤所以想問看看不好意思麻煩各位了 (Impulse Noise) prob = StrToInt(Form11->Edit1->Text); level = StrToInt(Form11->Edit2->Text); randomize(); for (int y = 0;y < nBitmap->Height;y++) { aptr = (Byte*)nBitmap->ScanLine[y]; for (int x = 0;x < nBitmap->Width;x++) if (random(100) <= prob) { pix1 = cp * x; aptr[pix1] = (Byte)(aptr[pix1]+level); aptr[pix1+1] = (Byte)(aptr[pix1+1]+level); aptr[pix1+2] = (Byte)(aptr[pix1+2]+level); } } (Gaussian Noise) mean = StrToInt(Form11->Edit1->Text); sd = StrToFloat(Form11->Edit2->Text); //ShowMessage("Mean = "+IntToStr(mean)+",\nSD ="+FloatToStr(sd)+"."); randomize(); for (int y = 0;y < nBitmap->Height;y++) { aptr = (Byte*)nBitmap->ScanLine[y]; for (int x = 0;x < nBitmap->Width;x++) { total = 0.0; for (int k = 0;k < 10;k++) { ran = (float)(random(100)+1) / 100; total += (float)sqrt12 * sd * (ran - 0.5); } total /= (float)sqrt10; total += (float)mean; pix1 = cp * x; sum1 = total+(float)aptr[pix1]; sum2 = total+(float)aptr[pix1+1]; sum3 = total+(float)aptr[pix1+2]; if (sum1 < 0.0) sum1 = 0.0; if (sum2 < 0.0) sum2 = 0.0; if (sum3 < 0.0) sum3 = 0.0; aptr[pix1] = (Byte)(sum1); aptr[pix1+1] = (Byte)(sum2); aptr[pix1+2] = (Byte)(sum3); } } (Uniform Noise) mean = StrToInt(Form11->Edit1->Text); sd = StrToFloat(Form11->Edit2->Text); randomize(); for (int y = 0;y < nBitmap->Height;y++) { aptr = (Byte*)nBitmap->ScanLine[y]; for (int x = 0;x < nBitmap->Width;x++) { ran = (float)(random(100)+1) / 100; total = ran - 0.5; total *= (float)sqrt12; total *= sd; total += (float)mean; pix1 = cp * x; sum1 = total+(float)aptr[pix1]; sum2 = total+(float)aptr[pix1+1]; sum3 = total+(float)aptr[pix1+2]; if (sum1 < 0.0) sum1 = 0.0; if (sum2 < 0.0) sum2 = 0.0; if (sum3 < 0.0) sum3 = 0.0; aptr[pix1] = (Byte)(sum1); aptr[pix1+1] = (Byte)(sum2); aptr[pix1+2] = (Byte)(sum3); } } -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 203.64.186.243

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pinchieh

04/09 10:55, , 1^F

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VictorTom

04/09 11:22, , 2^F

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VictorTom

04/09 11:23, , 3^F

04/09 11:23, 3^F