[問題] socket多人連線

看板AndroidDev作者 (原則)時間12年前 (2011/12/18 13:11), 編輯推噓3(300)
留言3則, 3人參與, 最新討論串1/1
小弟因為休課要交份期末project 目前打算做兩隻手機連線玩剪刀石頭布 因為前幾次作業有寫過socket所以打算用上次的改 上次的作業是可以多人連線猜數字 ex.解答為5678,若猜4678會回應說3A0B,A表示數字位置都對,B表示數字對位置不對 server: package hw_2; import java.io.IOException; import java.net.ServerSocket; import java.net.Socket; public class server { public static void main(String[] args) throws IOException{ int listenPort= 8888; ServerSocket serverSocket= null; Socket clientSocket= null; try { serverSocket= new ServerSocket(listenPort); System.out.println("the server information:"+ serverSocket.getLocalSocketAddress()); Thread thread= null; while (true) { System.out.println("server start!"); clientSocket= serverSocket.accept(); thread = new Thread(new serverthread(clientSocket)); thread.start(); } } catch (IOException e) { System.out.println("some error:" + e.getMessage()); } } } thread: package hw_2; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintStream; import java.net.Socket; class serverthread implements Runnable{ Socket clientSocket= null; PrintStream out = null; BufferedReader in = null; public serverthread(Socket s) { this.clientSocket= s; } public void run() { System.out.println("the client information :"+ clientSocket.getRemoteSocketAddress()); try { out = new PrintStream(clientSocket.getOutputStream()); in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream())); String number="5678";//欲猜測之數字 String str= in.readLine(); int a=0; int b=0; String answer; if(str.charAt(0)==number.charAt(0)) {a=a+1;} else if(str.charAt(0)==number.charAt(1) || str.charAt(0)==number.charAt(2) || str.charAt(0)==number.charAt(3)) {b=b+1;} if (str.charAt(1)==number.charAt(1)) {a=a+1;} else if (str.charAt(1)==number.charAt(0) || str.charAt(1)==number.charAt(2) || str.charAt(1)==number.charAt(3)) {b=b+1;} if (str.charAt(2)==number.charAt(2)) {a=a+1;} else if (str.charAt(2)==number.charAt(0) || str.charAt(2)==number.charAt(1) || str.charAt(2)==number.charAt(3)) {b=b+1;} if (str.charAt(3)==number.charAt(3)) {a=a+1;} else if (str.charAt(3)==number.charAt(0) || str.charAt(3)==number.charAt(1) || str.charAt(3)==number.charAt(2)) {b=b+1;} answer=a+"A"+b+"B"; out.println(answer); out.flush(); out.close(); in.close(); clientSocket.close(); } catch (IOException e) { System.out.println("Error:"+e.getMessage()); } } } 大至上了解多人連線的方法,但是如何同步不太了解怎麼寫 有請版上大大指點迷津一下感恩~ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.37.22.48

12/18 13:45, , 1F
建議轉到JAVA版
12/18 13:45, 1F

12/18 15:02, , 2F
啊不就執行緒... 會1v1就自然而然會NvN了吧?
12/18 15:02, 2F

12/19 10:35, , 3F
又在考試了
12/19 10:35, 3F
文章代碼(AID): #1ExNN_G- (AndroidDev)