[問題] 請幫忙看Get傳值語法
問題有點low,因為非本科,
公司網站有些問題,只好硬著頭皮上
小弟將問題簡化表示在以下網址 : study.elhomeo.com
在文字框修正數字後,要回傳一組資料給後端 stk_test1.php
但就是收不到, 看不出哪裡出問題了,只好上來請高手指教. 感謝
index.php
---------------
<script type="text/javascript">
var xmlHttp;
var json_object = new Object();
function upt(pid,pqty,pos,status) {
var str = "stk_test1.php?action=saveqty&id=" + pid + "&qty=" + pqty +
"&pos=" + pos + "&status=" + status;
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
} else { // code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
document.getElementById(pos).innerHTML= str;
xmlhttp.onreadystatechange=function() {
if (xmlhttp.readyState==4 && xmlhttp.status==200) {
if (xmlhttp.responseText){
document.getElementById(pos).innerHTML=xmlhttp.responseText; }
}
}
xmlhttp.open("GET",str,false);
xmlhttp.send();
}
</script>
<body>
<div id="pos1">001</div>
<form action="">
<INPUT id="qty" type="text" size=6 VALUE="999"
onblur="upt(\'1\',this.value,\'pos1\',\'1\')">
</form>
</body>
stk_test1.php
-----------------
<?php
if (isset($_Get['action']) && ($_Get['action'] == 'saveqty')) {
$p_id = $_Get['id'];
$p_qty = $_Get['qty'];
$p_pos = $_Get['pos'];
$p_status = $_Get['status'];
$arr = 'result:'.$p_id.$p_qty.$p_pos.$p_status;
echo $arr;
}
?>
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